that second equation just isn't right. You need to divide both MBP and Wolfnote into five separately, and add them together. There's no need for the additional +2. ([MBP/5]*2)+([Wolfnote/5]*2)=Bayonets!!!
Lessee if I can answer this for yee... You're attempting to do abstract math, but we're dealing with actualities (ie: people)
Wolfnote(WN)=5 Mark Birtles Project(MBP)=5 Renegade Cop(RC)=2 Bayonets!!!(B!!!)=4
So: MBP/5=1, WN/5=1 1*2=1+1 (hence the multiplication) B!!! = [(2/3WN)+(2/3MPB)] but B!!! =/= [(1/5WN)+(1/5MBP)]+2, because the additional two do not come from outside of the MBP/WN equation.
Also, whether I stated it or not, the first equation isn't accurate either, since B!!!/2 =2, and RC =2*, thus B+RC=4, while MBP=5, y'dig?
my equations all seem perfectly valid & interoperative. I even laid out what all the variables are. There were five members of the Wolfnote. The wolfnote broke up, thus, were divided into five separate units. Now, if you take one of those units, a wolfnote, you might say, and multiply it by itself, a wolfnote, or add itself, either way, you get two wolfnotes. The same for the mark birtles project. But by removing the addition, or multiplication, from their original contexts, you change their values, leaving it impossible to differentiate between wolfnotes, and birtles'. Now Bayonets is made up of two fifths of wolfnote, and two fifths of the mark birtles project, thus equaling four members. Thus, "Bayonets!!!=([MBP/5]+1)+([WN/5]+1) Maybe you were confused because I was showing how the underlying equations worked, rather than just explaining myself in the first place?
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that second equation just isn't right. You need to divide both MBP and Wolfnote into five separately, and add them together. There's no need for the additional +2. ([MBP/5]*2)+([Wolfnote/5]*2)=Bayonets!!!
1. Your original equation was
[(Wolfnote/5)+1]+[(Mark Birtles Project/5)+1]=Bayonets!!!
whence the +2.
2. Why isn't adding MBP and Wolfnote together and dividing by five the same thing as dividing each by five separately and then adding the results?
3. Where'd this *2 stuff come from all of a sudden? (vd. point 1)
Lessee if I can answer this for yee...
You're attempting to do abstract math, but we're dealing with actualities (ie: people)
Wolfnote(WN)=5
Mark Birtles Project(MBP)=5
Renegade Cop(RC)=2
Bayonets!!!(B!!!)=4
So: MBP/5=1, WN/5=1
1*2=1+1 (hence the multiplication)
B!!! = [(2/3WN)+(2/3MPB)]
but
B!!! =/= [(1/5WN)+(1/5MBP)]+2,
because the additional two do not come from outside of the MBP/WN equation.
Also, whether I stated it or not, the first equation isn't accurate either, since B!!!/2 =2, and RC =2*, thus B+RC=4, while MBP=5, y'dig?
(*Though hopefully RC will come to =3)
I ain't updatin' shit 'til you make up your mind, homes.
make up my mind?
Yeah, you give a different (and incompatible) equation every time :)
my equations all seem perfectly valid & interoperative.
I even laid out what all the variables are.
There were five members of the Wolfnote. The wolfnote broke up, thus, were divided into five separate units. Now, if you take one of those units, a wolfnote, you might say, and multiply it by itself, a wolfnote, or add itself, either way, you get two wolfnotes. The same for the mark birtles project. But by removing the addition, or multiplication, from their original contexts, you change their values, leaving it impossible to differentiate between wolfnotes, and birtles'. Now Bayonets is made up of two fifths of wolfnote, and two fifths of the mark birtles project, thus equaling four members. Thus, "Bayonets!!!=([MBP/5]+1)+([WN/5]+1)
Maybe you were confused because I was showing how the underlying equations worked, rather than just explaining myself in the first place?
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